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The impulse theorem states that the impulse exerted on an object is equal to the change in the object's momentum. In formula, we can write it as:
I = Δp
Where:
•I is the impulse.
•Δp is the change in momentum.
Momentum p is defined as the product of mass m and velocity v:
p = m * v
If we know the force Fapplied to the mass and the time t during which this force is applied, the impulse I can be calculated as:
I = F * t
To find the initial velocity v0, we can express the change in momentum as:
Δp = m * v - m * v0
Where:
•v is the final velocity.
•v0 is the initial velocity.
Using the impulse theorem:
F * t = m * v - m * v0
From which we can isolate the initial velocity v0:
v0 = v - (F * t) / m
Example Calculation:
Suppose we have a mass with the following characteristics:
•Mass m = 10 kg
•A constant force F = 50 N is applied for t = 4 s
•Final velocity v = 30 m/s
Let's calculate the initial velocity v0:
1.Calculate the impulse:
I = F * t = 50 N * 4 s = 200 Ns
2.Using the formula to find v0:
v0 = v - (I / m)
v0 = 30 m/s - (200 Ns / 10 kg)
v0 = 30 m/s - 20 m/s
v0 = 10 m/s
Therefore, the initial velocity of the mass was 10 m/s.
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